60=x^2/(1-0.5x)*(2-0.5x)

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Solution for 60=x^2/(1-0.5x)*(2-0.5x) equation: 



60=x^2/(1-0.5x)(2-0.5x)

We move all terms to the left:

60-(x^2/(1-0.5x)(2-0.5x))=0



Domain of the equation: (1-0.5x)(2-0.5x))!=0

We move all terms containing x to the left, all other terms to the right

-0.5x)(2-0.5x)!=-1

x∈R



We add all the numbers together, and all the variables

-(x^2/(-0.5x+1)(-0.5x+2))+60=0

We multiply parentheses ..

-(x^2/(+0x^2+0x+0x+2))+60=0

We multiply all the terms by the denominator


-(x^2+60*(+0x^2+0x+0x+2))=0



We calculate terms in parentheses: -(x^2+60*(+0x^2+0x+0x+2)), so:

x^2+60*(+0x^2+0x+0x+2)

We multiply parentheses

x^2+0x^2+0x+0x+120

We add all the numbers together, and all the variables

2x^2+2x+120

Back to the equation:

-(2x^2+2x+120)



We get rid of parentheses

-2x^2-2x-120=0

a = -2; b = -2; c = -120;
Δ = b2-4ac
Δ = -22-4·(-2)·(-120)
Δ = -956
Delta is less than zero, so there is no solution for the equation

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